MCQ
In the figure shown $\frac{{\sin i}}{{\sin r}}$ is equal to :
- A$\frac{{\mu _2^2}}{{{\mu _3}\,{\mu _1}}}$
- ✓$\frac{{{\mu _3}}}{{{\mu _1}}}$
- C$\frac{{{\mu _3}\,{\mu _1}}}{{\mu _2^2}}$
- Dnone
✓
Answer
Correct option: B.
$\frac{{{\mu _3}}}{{{\mu _1}}}$
b
$\mu_{1} \sin i_{1}=\mu_{3} \sin i_{3}$
$\mu_{1} \sin i_{1}=\mu_{3} \sin i_{3}$
$\therefore \mu_{1} \sin i=\mu_{3} \sin r$ or $\frac{\sin i}{\sin r}=\frac{\mu_{3}}{\mu_{1}}$
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