Question
In the figures below, find the value of ‘x’.



ii. In ∆PQR, ∠Q = 90°.
Hence, side PR is the hypotenuse.
According to Pythagoras’ theorem,
l(PR)² = l(PQ)² + l(QR)²
∴ 412 = 92 + x²
∴ 1681 = 81 + x²
∴ 1681 – 81 = x²
∴ 1600 = x²
∴ x² = 1600
∴ x² = 40²
∴ x = 40 units
iii. In AEDF, ∠D = 90°.
Hence, side EF is the hypotenuse.
According to Pythagoras’ theorem,
l(EF)² = l(ED)² + l(DF)²
∴ 17² = x² + 8²
∴ 289 = x² + 64
∴ 289 – 64 = x²
∴ 225 = x²
∴ x² = 225
∴ x² = 15²
∴ x = 15 units
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Days
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Mon.
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Tues.
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Wed.
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Thurs.
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Fri.
|
Sat.
|
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Newspaper readers
|
350
|
400
|
500
|
450
|
550
|
450
|
|
Magazine readers
|
200
|
450
|
300
|
250
|
100
|
50 |
| Year | 1992 | 1993 | 1994 | 1995 | 1996 | 1997 |
| Manure (in thousand tonnes) | 15 | 35 | 45 | 30 | 40 | 20 |

| Month | January | February | March | April | May | June |
| Number of hours of sunshine in Aberdeen | $2$ | $3\frac14$ | $4$ | $4\frac12$ | $7\frac34$ | $8$ |
| Number of hours of sunshine in Margate | $1\frac12$ | $3$ | $3\frac12$ | $6$ | $5\frac12$ | $6\frac12$ |
|
Year
|
1998-99
|
1999-2000
|
2000-01
|
2001-02
|
2002-03
|
|
Interest (in thousand crore rupees)
|
70
|
84
|
98
|
106
|
120
|