MCQ
In the following figure, $\triangle\text{ABC}$ is an equilateral triangle. Find $\angle\text{x}$


- A$30^\circ$
- B$45^\circ$
- ✓$60^\circ$
- D$90^\circ $

$\angle\text{ABC}=60^\circ$
$\therefore\angle\text{ABD}=180^\circ-60^\circ=120^\circ$
$\therefore\text{x}=180^\circ-(120^\circ+30^\circ)$
$=30^\circ$
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