MCQ
In the following given reaction ' $A$ ' is


- A

- B

- C

- ✓








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$C{H_3}CHO\mathop {\xrightarrow{{(i)\,NaCN/HCl}}}\limits_{(ii)\,{H_2}O/{H^ \oplus }/\Delta } (A)\mathop {\xrightarrow{{Fenton}}}\limits_{reagent} (B)$
$(B)$ will be :
$A\,\xrightarrow[{1200\,\,atm}]{{470\,\,K}}B$
$A\,\xrightarrow[{C{O_2}\, - \,atm}]{{570\,\,K}}C$
takes places through the mechanism given below :
$NO + Br _2 \Leftrightarrow NOBr _2 \text { (fast) }$
$NOBr _2+ NO \rightarrow 2 NOBr \text { (slow) }$
The overall order of the reaction is $.....$.