Download App

STD 11 - 3. Classification of elements and periodicity in properties — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 3. Classification of elements and periodicity in properties4 Marks
MCQ
In the following, the element with the highest electropositivity is
  • A
    Copper
  • ✓
    Caesium
  • C
    Barium
  • D
    Chromium
✓

Answer

Correct option: B.
Caesium
b
(b) Alkali metals are most electropositive and moreover, electropositive character increases down the group.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Beryllium resembles much with
→
Which element having following electronic configurations has minimum ionization potential
→
The standard potential of a $Co^{+2}| Co$  electrode is $-0.28\,V$  and the standard potential of the cell  $Pt|Ti^{2+} (aq),\, Ti^{3+} (aq)||Co^{2+} (aq)|Co(s)$ is $0.09\,\,V$.  What is the standard oxidation potential of the $Ti_{{\text{(aq}}.)}^{2 + }\,\,|\,\,Ti_{{\text{(aq}}.)}^{3 + }$ electrode ? ............. $\mathrm{V}$
→
Which of the following sets of atomic numbers corresponds to elements of group $16$ ?
→
Which one of the following is most soluble
→
Identify the wrong statement in the following.
→
$H-$ bond is not present in
→
When beryllium is bombarded with $\alpha $-particles, extremely penetrating radiations which cannot be deflected by electrical or magnetic field are given out. These are
→
$(i)\,\,\begin{matrix}
   CHO\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   {{(CH-OH)}_{3}}\,\,\,\,\,\,  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   \,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}\xrightarrow{4HI{{O}_{4}}} Product$ $(ii)\,\,\begin{matrix}
   C{{H}_{2}}OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   {{(CH-OH)}_{4}}\,\,\,\,\,\,  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   \,\,C{{H}_{2}}-OH\,\,\,\,\,\,\,\,\,\,  \\
\end{matrix}\xrightarrow{5HI{{O}_{4}}} Product$

Ratio of moles of formic acid obtained in reaction $(i)$ and reaction $(ii)$ is

→
${A} \xrightarrow{{4\,KO{H_1}{O_2}}}\mathop {2{B} }\limits_{(Green)}  + 2{H_2}O$
$3{B} \xrightarrow{{4\,HCl}}\mathop {2C}\limits_{(Purple)}  + Mn{O_2} + 2{H_2}O$
$3{C} \xrightarrow{{{H_2}O,KI}}2{A}  + 2KOH + {D} $
In the above sequence of reactions, ${A}$ and ${D} $ ,  respectively are
→