Question
In the given circle with diameter AB, find the value of x.
✓
Answer
∠ABD = ∠ACD = 30° [Angle in the same segment]
Now in ΔADB ,
∠BAD + ∠ADB + ∠ABD = 180° [angles of a triangle]
But, ∠ADB = 90° [ Angle in a semi-circle]
∴ x + 90° + 30° = 180°
⇒ x = 180° -120°
⇒ x = 60°
Now in ΔADB ,
∠BAD + ∠ADB + ∠ABD = 180° [angles of a triangle]
But, ∠ADB = 90° [ Angle in a semi-circle]
∴ x + 90° + 30° = 180°
⇒ x = 180° -120°
⇒ x = 60°
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