MCQ
- A45º
- B35º
- C25º
- D30º
✓
Answer
- 35º
Solution:
$\angle\text{ABC}=\angle\text{BCD}=45^\circ$ (Alternate interior angles)
In $\triangle\text{COD}$
$\angle\text{COD}+\angle\text{CDO}+\angle\text{DCO}=180^\circ$ (Angle sum property)
$\angle\text{CDO}=180^\circ-100^\circ-45^\circ$
$\angle\text{CDO}=35^\circ.$
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