Question
In the given figure, $\angle \mathrm{BAD}=65^{\circ}, \angle \mathrm{ABD}=70^{\circ}$ and $\angle \mathrm{BDC}=45^{\circ}$. Find
(a) $\angle \mathrm{BCD}$
(b) $\angle \mathrm{ADB}$. Hence, show that AC is a diameter of the circle.

(a) $\angle \mathrm{BCD}$
(b) $\angle \mathrm{ADB}$. Hence, show that AC is a diameter of the circle.


