MCQ
- A25°
- B40°
- C50°
- D30°
✓
Answer
- 30°
Solution:
In $\triangle\text{ABC}$
$\angle\text{ABC}+\angle\text{BAC}+\angle\text{ACB}=180^\circ$(Angle sum property)
$\angle\text{ABC}=180^\circ-90^\circ-40^\circ$
$\angle\text{ABC}=50^\circ$
In $\triangle\text{BED}$
$\angle\text{BED}+\angle\text{EBD}+\angle\text{BDE}=180^\circ$(Angle sum property)
$\angle\text{EBD}=180^\circ-50^\circ-100^\circ$
$\angle\text{EBD}=30^\circ$
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