Question
In the given figure, $\angle\text{ABC}=90^\circ$ and $\text{BD} \perp\text{AC.}$ If AB = 5.7cm, BD = 3.8cm and CD = 5.4cm, find BC.

Answer

We have, $\angle\text{ABC}=90^\circ$ and $\text{BD}\perp\text{AC}$
In $\triangle\text{ABC}$ and $\triangle\text{BDC}$
$\angle\text{ABC}=\angle\text{BDC}$ [Each 90°]
$\angle\text{C}=\angle\text{C}$ [Commom]
Then, $\triangle\text{ABC}\sim\triangle\text{BDC}$ [By AA similarity]
$\therefore\frac{\text{AB}}{\text{BD}}=\frac{\text{BC}}{\text{DC}}$ [Corresponding parts of similar $\triangle$ are proportional]
$\Rightarrow\frac{5.7}{3.8}=\frac{\text{BC}}{5.4}$
$\Rightarrow\text{BC}=\frac{5.7}{3.8}\times8.1\text{cm}$

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