MCQ
In the given figure force on wire $ABC$ will be $(B = 2T)$


- A$4(3+2\pi ) N$
- ✓$20\,N$
- C$10\,N$
- D$40\,N$

Force on $\mathrm{BC}=16 \mathrm{\,N}$ (left)
so force on $\mathrm{ABC}=\sqrt{(12)^{2}+(16)^{2}}=20 \mathrm{\,N}$
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