Question
In the given figure, $\triangle\text{ABC}$ and $\triangle\text{DBC}$ have the same base BC. If AD and BC intersect at O, prove that $\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{DBC})}=\frac{\text{AO}}{\text{DO}}.$




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| Country | India | China | Russia | USA | Others | Total |
| Percentage poulation | 15 | 20 | a | a | 25 | 100 |