In the given network current through branch $BG$ is almost equal to ............ $A$
Diffcult
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Eeq $=\frac{300}{19}+15=\frac{585}{19} \mathrm{\,V}$
Req $=\frac{20}{19}+2=\frac{58}{19}$
$I=\frac{585}{58} \approx 10 \,A$
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