$CH_3-CH_2-OH$ $\mathop {\xrightarrow{{(i)\,KMn{O_4}/\mathop O\limits^\Theta H/\Delta }}}\limits_{(ii)\,{H^ \oplus }} (A)\mathop {\xrightarrow{{(i)\,SOC{l_2}}}}\limits_{(ii)\,N{H_3}/\Delta } (B)$ $\xrightarrow{{B{r_2}/KOH}}(C)$
$(C)$ will be :
$CH _3- CH _2- OH \underset{\text { (ii) } H ^{\oplus}}{\stackrel{\text { (i) } KMnO _4 / O ^{\ominus} H / \Delta}{\longrightarrow}} CH _3-\underset{\text { (A) }}{ COOH } \underset{\text { (ii) } NH _3 / \Delta}{\stackrel{\text { (i) } SOCl _2}{\longrightarrow}} CH _3-CONH _2 \stackrel{ Br _2 / KOH }{\longrightarrow} CH _3 NH _2$
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Given : $AB$ is $100\%$ ionised at boiling point of the solution, ($K_b / K_f $) water $= 0.3$
| Rate Constant | Activation energy | |
| Step $1$ | $k_1$ | $E_{a_1} = 180\ kJ/mol$ |
| Step $2$ | $k_2$ | $E_{a_2} = 80\ kJ/mol$ |
| Step $3$ | $k_3$ |
$E_{a_3} = 50\ kJ/mol$ |
| Column $I$ | Column $II$ |
| $(A)$ $\mathrm{Cu}+$ dil $\mathrm{HNO}_3$ | $(p)$ NO |
| $(B)$ $\mathrm{Cu}+$ conc $\mathrm{HNO}_3$ | $(q)$ $\mathrm{NO}_2$ |
| $(C)$ $\mathrm{Zn}+$ dil $\mathrm{HNO}_3$ | $(r)$ $\mathrm{N}_2 \mathrm{O}$ |
| $(D)$ $\mathrm{Zn}+$ conc $\mathrm{HNO}_3$ | $(s)$ $\mathrm{Cu}\left(\mathrm{NO}_3\right)_2$ |
| $(t)$ $ \mathrm{Zn}\left(\mathrm{NO}_3\right)_2$ |