MCQ
In the given reaction sequence $[X]$ will be
- ABenzoic acid
- BSalicylic acid
- CPhenol
- ✓Aniline
✓
Answer
Correct option: D.
Aniline
d
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Consider following compounds :
$(I)\, H_3X - NCS$ $(II)\,H_3Y - NCS$ $(III)\, (H_3X)_2O$ $(IV)\, (H_3Y)_2O$
The incorrect statement regarding given compound is
→$(I)\, H_3X - NCS$ $(II)\,H_3Y - NCS$ $(III)\, (H_3X)_2O$ $(IV)\, (H_3Y)_2O$
The incorrect statement regarding given compound is
$ \mathrm{Ag}^{+}+\mathrm{NH}_3 \rightleftharpoons\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)^{+}\right] ; \mathrm{k}_1=3.5 \times 10^{-3} $
→$ {\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)\right]^{+}+\mathrm{NH}_3 \rightleftharpoons\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+} ; \mathrm{k}_2=1.7 \times 10^{-3}}$
then the formation constant of $\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}$is
$EAN$ of $Fe$ in $[Fe(C_2O_4)_3]^{3-}$
→Match the metal column $I$ with the coordination compounds/enzymes column $II$
→| column $I$ Metals | column $II$ Coordination compounds |
| $a.$ $Co$ | $i.$ Wilkinson catalyst |
| $b.$ $Zn$ | $ii.$ Chlorophyll |
| $c.$ $Rh$ | $iii.$ Vitamin $B_{12}$ |
| $d.$ $Mg$ | $iv.$ Carbonic anhydrase |
Any $p-$ orbital can accommodate up to:
→At $25\,^o C$, the dissociation constant of a base $BOH$ is $1.0 \times {10^{ - 12}}$. The concentration of Hydroxyl ions in $0.01\, M$ aqueous solution of the base would be
→Which of the following pairs show reverse properties on moving along a period from left to right and from top to down in a group
Assign $A, B, C, D$ from given type of reaction. $C\left( s \right) + {O_2}\left( g \right)\xrightarrow{\Delta }C{O_2} \uparrow $
→Ethyl amine undergoes oxidation in the presence of $KMn{O_4}$ to form
→The outer electronic structure of lawrencium (atomic number $103$) is
→