MCQ
In the given reaction $[X]$ will be


- A$C_6H_5NH_2$
- B$C_6H_5NHOH$
- ✓$p-$ amino phenol
- DHydrazobenzene


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$(1)$ $NaN{H_2};\mathop {C{H_3}}\limits^{{\text{a}}\,\,\,\,\,\,\,} C{H_2}Br$:${H_2},{\text{ }}\mathop {{\text{(one mole)}}}\limits^{\text{b}} {\text{ }}Pd{\text{ or }}Ni$
$(2)$ $NaN{H_2};C{H_3}C{H_2}C{H_2}Br$:${H_2}{\text{ (two moles) }}Pd{\text{ or }}Ni$
$(3)$ $NaN{H_2};C{H_3}C{H_2}C{H_2}Br$:${H_2},{\text{ (one mole) }}Pd{\text{ or }}Ni$
$(4)$ $NaN{H_2};C{H_3}C{H_2}C{H_2}Br$:$B{H_3},{H_2}{O_2},O{H^ - }$
$(A)$ Na and excess of $NH _3$
$(B)$ $K$ and excess of $O _2$
$(C)$ $Cu$ and dilute $HNO _3$
$(D)$ $O _2$ and $2$-ethylanthraquinol
Reason : $NF_3$ ionizes to give $F^-$ ions in aqueous solution.