- A$BC{l_3}$
- ✓$P{H_3}$
- CBoth
- DNone
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$[\Lambda_{\mathrm{H}^{+}}^{\circ}=350 \,\mathrm{~S}\, \mathrm{~cm}^{2}\, \mathrm{~mol}^{-1},\Lambda_{\mathrm{CH}_{3} \mathrm{COO}^{-}}^{\circ}=50\, \mathrm{~S}\, \mathrm{~cm}^{2}\, \mathrm{~mol}^{-1}]$
$C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,}{\mathop{\overset{OH}{\mathop{\overset{|\,\,\,\,}{\mathop{C-}}\,}}\,}}\,}}\,C{{H}_{2}}-\underset{C{{H}_{3}}\,}{\mathop{\underset{|\,\,\,\,\,\,\,}{\mathop{CH-}}\,}}\,C{{H}_{3}}$
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - CH - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {C{H_3} - C{H_2} - OH}\limits_{{\rm{III}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,Ph}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}}
\end{array}}\limits_{{\rm{IV}}} $