MCQ
In the relation:
$y=a \cos (\omega t+K x)$, the dimensional formula for $K x$ is the same as that of:
  • A
    $\frac{y a}{\omega t}$
  • B
    $\frac{a}{\omega}$
  • C
    $\frac{w t}{a}$
  • D
    $\frac{a}{y}$

Answer

D. $\frac{a}{y}$
Explanation:Here, $[ a ]=[ y ]$. So, $\frac{a}{y}$ is dimensionless. Same is the case with Kx .

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