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2. Electric potential and capacitance — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics2. Electric potential and capacitance1 Mark
MCQ
In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be (Given area of plate $=A$ )
  • A
    $\frac{25}{6} \frac{{K} \varepsilon_{0} {A}}{{d}}$
  • ✓
    $\frac{15}{34} \frac{{K\varepsilon}_{0} {A}}{{d}}$
  • C
    $\frac{15}{6} \frac{{K} \varepsilon_{0} {A}}{{d}}$
  • D
    $\frac{9}{6} \frac{{K} \varepsilon_{0} {A}}{{d}}$
✓

Answer

Correct option: B.
$\frac{15}{34} \frac{{K\varepsilon}_{0} {A}}{{d}}$
b
$\frac{1}{C_{eq}}=\frac{d}{K \varepsilon_{0} A}+\frac{2 d}{3 K \varepsilon_{0} A}+\frac{3 d}{5 K \varepsilon_{0} A}$

$C_{eq}=\frac{15 K \varepsilon_{0} A}{34 d}$

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