MCQ
In the transition of $Zn$ atoms to $Z{n^{ + + }}$ ions there is a decrease in the
- ✓Number of valency electrons
- BAtomic weight
- CAtomic number
- DEquivalent weight
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${{O}_{(g)}}+{{e}^{-}}=O_{(g)}^{-}\Delta {{H}^{o}}=-142\ kJ\,mo{{l}^{-1}}$
$O_{(g)}^{-}+{{e}^{-}}=O_{(g)}^{2-}\Delta {{H}^{o}}=844\ kJ\,mo{{l}^{-1}}$
| List $I$ | List $II$ | ||
| $A$ | $XeF_4$ | $1$ | Pyramidal |
| $B$ | $XeF_6$ | $2$ | $T-$ shape |
| $C$ | $XeO_3$ | $3$ | Distorted octahedral |
| $D$ | $XeOF_2$ | $4$ | Square planar |
Assertion $A :$ Dipole-dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason $R$ : Fluorine is the most electronegative element and hydrogen bonds in $HF$ are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.
$\Lambda_{ m }^{\alpha}=133.4\,\left( AgNO _{3}\right) ; \Lambda_{ m }^{\alpha}=149.9( KCl )$
$\Lambda_{ m }^{\alpha}=144.9\, S\, cm ^{2} \,mol ^{-1}\left( KNO _{3}\right)$
the molar conductivity at infinite dilution for $AgCl$ is $.......\, S \,cm ^{2}\, mol ^{-1}$