MCQ
In this diol


- ✓$OH$ at $C_2$ is more basic than that of at $C_5$
- B$OH$ at $C_2$ is more acidic than at $C_5.$
- Cboth have same basicity
- Dboth have same acidic strength

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Reason: Due to formation of a complex
$CH_3-CH=CH-CH_2-OH$ $\xrightarrow[{{S}_{{{N}^{1}}}}]{HBr}$ $[P]$
In the given reaction the product $[P]$ is :
$\begin{array}{*{20}{c}}
O\\
{||}\\
{C{H_3} - C - C{H_3}}
\end{array}$ $ + \begin{array}{*{20}{c}}
{C{H_2}OH}\\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_2}OH}
\end{array}$ $\overset{HCl}{\longleftrightarrow}$ ?
