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Triangles — Maths STD 10 — Question

Gujarat BoardEnglish MediumSTD 10MathsTriangles1 Mark
Question
In $\triangle ABC$ if $AB = BC =\frac{ AC }{\sqrt{2}}$ then $\angle B =\ldots \ldots \ldots .\left(90^{\circ}\right.$, More than $90^{\circ}$, Less than $\left.90^{\circ}\right)$
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Answer

$90^{\circ}$

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