Question
In $\triangle ABC$, point $D$ divides $AB$ in the ratio $5: 7$, Find: $\frac{ AE }{ EC }$
✓
Answer
Considering $DE \| BC $
$ \frac{ AD }{ DB }=\frac{ AE }{\overline{ EC }} $
$ \Rightarrow \frac{ AE }{ EC }=\frac{ AD }{ DB } $
$ \Rightarrow \frac{ AE }{ EC }=\frac{5}{7} .$
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