Question
In $\triangle\text{ABC}$ and $\triangle\text{DEF,}$ it is given that AB = DE and BC = EF. In order that $\triangle\text{ABC}\cong\triangle\text{DEF},$ we must have:
✓
Answer
- $\angle\text{B}=\angle\text{E}$
Solution:
In $\triangle\text{ABC}$ and $\triangle\text{DEF},$
AB = DE and BC = EF
SO, the induded angles should be equal for the triangle to be congurent by the SAS congruence criterion.
Thus, we must have $\angle\text{B}=\angle\text{E}.$
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