MCQ
In $\triangle\text{ABC}$ and $\triangle\text{DEF}$ its is given that $\angle\text{B}=\angle\text{E}$ and $\angle\text{C}=\angle\text{F}$ in order that $\triangle\text{ABC}≅\triangle\text{DEF}$ we must have,
  • A
    AC = DE
  • B
    BC = EF
  • C
    AB = DF
  • D
    $\angle\text{A}=\angle\text{D}$

Answer

  1. BC = EF
    Solution:
    In $\triangle\text{ABC}$ and $\triangle\text{DEF}$
    $\angle\text{B}=\angle\text{E}$ and $\angle\text{C}=\angle\text{F}$
    For congruence, BC = EF
    Therefore by AAS axiom
    $\triangle\text{ABC}≅\triangle\text{DEF}$

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