Question
In $\triangle\text{ABC}$ and $\triangle\text{PQR},$ AB = PR and $\angle\text{A} = \angle\text{P}.$ Then, the two triangles will be congruent by SAS axiom if:
✓
Answer
- AC = PQ
Solution:
$\angle\text{A}$ is included between AB and AC and $\angle\text{P}$ is included between PQ and PR and corresponding sides must be equal. Since AB = PR, hence AC = PQ for the given triangles to be congruent by SAS axiom.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If one angle of a parallelogram is 24º less than twice the smallest angle, then the measure of the largest angle of the parallelogram is:
ABCD is a trapezium in which $\text{AB || DC}.$ M and N are the mid-points of AD and BC respectively. If AB = 12cm, MN = 14cm, then CD = ?
→Consider the following statement:
When two straight lines intersect:
When two straight lines intersect:
- Adjacent angles are complementary
- Adjacent angles are supplementary
- Opposite angles are equal
- Opposite angles are supplementary
The mean of first n natural numbers is:
A conical tent is to accommodate $11$ persons such that each person occpies $4\ m^2$ of space on the ground. They have $220\ m^3$ of air to breathe. The height of the cone is:
→In the given figure, the ratio $AD$ to $DC$ is$ 3$ to $2$. If the area of $\triangle\text{ABC}$ is $40\ cm^2,$ what is the area of $\triangle\text{BDC}?$
→If $a^2 + b^2 + c^2 - ab - bc - ca =0,$ then:
→Length of perpendicular drawn on smallest side of scalene triangle is:
More than’ cumulative frequency table for a given data is as follows: Then, the frequency of the class interval 70-80 is:
|
Marks
|
More than 89
|
More than 79
|
More than 69
|
More than 59
|
|
Cumulative frequency
|
8
|
18
|
30
|
65
|
If the volume of a sphere is $4851\ cm^3,$ then its surface area is:
→