Download App

Quadrilaterals — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsQuadrilaterals1 Mark
MCQ
In $\triangle\text{ABC}, EF$ is the line segment joining the mid-points of the sides $AB$ and $AC. BC = 7.2\ cm,$ Find $EF = ?$
  • A
    $3.4\ cm$
  • ✓
    $3.6\ cm$
  • C
    $3.5\ cm$
  • D
    $2.6\ cm$
✓

Answer

Correct option: B.
$3.6\ cm$

$ E$ and $F$ are midpoints of sides $AB$ and $AC.$ By midpoint theorem, $EF$ is parallel to $BC$ and $EF$ is $\frac{1}{2}$ of $BC.$
So, $\text{EF} = {1}{2}$ of $(7.2) = 3.6\text{cm}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Quadrilaterals→Quadrilaterals — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

The edges of a triangular board are$ 6\ cm, 8\ cm$ and $10\ cm.$ The cost of painting it at the rate of $70$ paise per $cm^2$ is:
→
$(256)^{0.16} \times(256)^{0.09}$
→
The radius of a hemispherical balloon increases from $6\ cm$ to $12\ cm$ as air is being pumped into it. The ratios of the surface areas of the balloon in the two cases is.
→
There are $50$ numbers. Each number is subtracted from $53$ and the difference between the mean of the numbers so obtained is found to be $3.5$. The mean of the given number is:
→
Two point having same abscissae but different ordinates lie on:
→
The value of 0.9999... when expressed as a fraction in the simplest form is
→
The ordinate of any point on $x-$axis is:
→
$\frac{\left(a^2-b^2\right)^3+\left(b^2-c^2\right)^3+\left(c^2-a^2\right)^3}{(a-b)^3+(b-c)^3+(c-a)^3}=$
→
If two angles are complements of each other, then each angle is:
→
The circumference of the base of a right circular cylinder is $44\ cm$. If its whole surface area is $968\ cm^2$ then the sum of its height and radius is:
→