Question
In what way is the electronic configuration of the transition elements different from that of the non transition elements?

Answer

Transition metals have a partially filled $d-$orbital. Therefore, the electronic configuration of transition elements is $(n -1)d^{1-10}ns^{0-2}.$ The non$-$transition elements either do not have a $d-$orbital or have a fully filled $d-$orbital. Therefore, the electronic configuration of non$-$transition elements is $ns^{1-2 }$ or $ns^{2 } \ np^{1-6}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The rate of reaction, $\ce{2NO + Cl2 \rightarrow 2NOCl}$ is doubled when concentration of $\ce{Cl2}$ is doubled and it becomes eight times when concentration of both $\ce{NO}$ and $\ce{Cl2}$ are doubled. Deduce the order of the reaction.
Write the reaction involved in the following:
  1. Etard reaction.
  2. Wolff-Kishner reduction.
Explain briefly how $+2$ state becomes more and more stable in the first half of the first row transition elements with increasing atomic number?
  1. Write structures of different isomeric amines corresponding to the molecular formula, $C_4H_{11}N.$
  2. Write $\text{IUPAC}$ names of all the isomers.
  3. What type of isomerism is exhibited by different pairs of amines?
What are enzymes?
Out of o-nitrophenol and p-nitrophenol, which is more volatile? Explain.
(i) Give two methods in which $> C = O$ group is converted into $> C H _2$ group.
(ii) In the purification of aldehydes sodium bi-sulphite is used, why?
What happens when the vapours of a primary, secondary and tertiary alcohol are passed over heated copper at 573 K temperature? Explain with chemical equation.
Write a note on primary structure of protein compounds.
Two half-reactions of an electrochemical cell are given below:
$MnO_4^- (aq) + 8 H^+ (aq) + 5e^– \rightarrow Mn^{2+} (aq) + 4H_2O (l), E^\circ = +1.51 V,$
$Sn^{2+} (aq) \rightarrow Sn^{4+} (aq) + 2e^–, E^\circ= +0.15 V.$
Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured.