MCQ
In which bond angle is the highest
- A$s{p^3}$
- B$s{p^2}$
- ✓$sp$
- D$s{p^3}d$
| Type | Bond angle |
| $sp^3$ | $109.5^o$ |
| $sp^2$ | $120^o$ |
| $sp^3d$ | $90^o$ and $102^o$ |
| $sp$ | $180^o$ |
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${N_2}(g)\, + \,{O_2}(g)\,\underset{{{k_2}}}{\overset{{{k_1}}}{\longleftrightarrow}}\,2NO(g)$
$C_0=Ce^{-2.1 \times 10^{-3}t}$ for the forward reaction and $C'_0=C'e^{-4.2 \times 10^{-4}t}$ for the backward reaction, hence $K_c$ for the above equilibrium is :-
$\left(1 F =96,500\, C\, mol ^{-1}\right)$
$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}} \\
|
\end{array}} \\
{C{H_3} - C - C{H_3}} \\
| \\
H
\end{array}{\mkern 1mu} $ $\mathop {\xrightarrow{{C{H_3}OBr}}}\limits_{C{H_3}OH} $