- A$NO$
- B${N_2}O$
- ✓$N{H_2}OH$
- D${N_2}{H_4}$
$x+2+(-2)+1=0$
$x+2-2+1=0$
$x=-1$
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Product $(B)$ of above reaction is
$C_2H_5-Br\overset{AgCN}{\rightarrow}A\overset{H_2/Ni}{\rightarrow}B$
Product $B$ is
$(I)$ $\begin{array}{*{20}{c}}
{C{H_2} - C{H_2} - C{H_2} - C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{O_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)$ $\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - C{H_2}OH} \\
{|\,} \\
{N{O_2}}
\end{array}$
$(III)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - C{H_2}OH} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{N{O_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$(IV)$ $CH_3-CH_2-CH_2-CH_2OH$
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