MCQ
In which pair second ion is more stable than first?


- A$(i)$ and $(ii)$
- ✓$(ii)$ and $(iii)$
- C$(ii)$ and $(iv)$
- D$(iii)$ and $(iv)$

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$0.48 + \log \left\{ { - \frac{{d[A]}}{{dt}}} \right\} = \log \left\{ { + \frac{{d[B]}}{{dt}}} \right\} + 0.7$
Then, $x : y$ is

$H_2C = CH - CH_2 - I \xrightarrow[CC{{l}_{4}}]{HI(excess)}$