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STD 11 - 9. Hydricarbon — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 9. Hydricarbon4 Marks
MCQ
In which reaction last product is $Ph -C \equiv CH$ ?
  • A
    $\begin{matrix}
       \,\,\,\,\,\,Br  \\
       \,\,\,|  \\
       {{C}_{6}}{{H}_{5}}-C-C{{H}_{3}}  \\
       \,\,\,|  \\
       \,\,\,\,\,Br  \\
    \end{matrix}\xrightarrow[Mineral\,\,oil,heat]{2NaN{{H}_{2}}}\xrightarrow{N{{H}_{4}}Cl}$
  • B
    ${{C}_{6}}{{H}_{5}}CH=C{{H}_{2}}\xrightarrow[CC{{l}_{4}}]{B{{r}_{2}}}\xrightarrow[Mineral\,\,oil,heat]{3NaN{{H}_{2}}}\xrightarrow{N{{H}_{4}}Cl}$
  • C
    $\begin{array}{*{20}{c}}
      {\,\,\,\,O} \\ 
      {\,\,\,||} \\ 
      {{C_6}{H_5} - C - C{H_3}} 
    \end{array}\xrightarrow{{PC{l_5}}}\xrightarrow[{\min eral\,oil,\,heat}]{{3NaN{H_2}}}\xrightarrow{{N{H_4}Cl}}$
  • ✓
    All
✓

Answer

Correct option: D.
All
d
$(d)$

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