MCQ
In $Xe{F_4}$ hybridization is
- ✓$s{p^3}{d^2}$
- B$s{p^3}$
- C$s{p^3}d$
- D$s{p^2}d$
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$(I)$ $Na_2O_2$
$(II)$ $O_2 [AsF_6]$
$(III)$ $CsO_2$
$(IV)$ $O_2$
then the solubility of $AB _{2}$ in pure water is......... $\times 10^{-4}$ $mol$ $L ^{-1}$.
[Assuming that neither kind of ion reacts with water]