($CIP$ rule) $-F > \, -CH_2Cl > \, -CH_2CH_2Br > \, -CH_2CH_2CH_2I$
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$(a)\;\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}(\mathrm{OH}) \mathrm{CH}_{3} \stackrel{\mathrm{conc.H}, \mathrm{SO}_{4}}{\longrightarrow}$
$(b)\;\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}(\mathrm{Br}) \mathrm{CH}_{3} \stackrel{\text { alc.KOH }}{\longrightarrow}$
$(c)\;\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}(\mathrm{Br}) \mathrm{CH}_{3} \xrightarrow[\text { It should be }\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CO}^{-} \mathrm{K}^{+}]{\text { given by } \mathrm{NTA}\left(\mathrm{CH}_{3}\right)_{3} \mathrm{O}^{-} \mathrm{K}^{+}}$
$(d)\;\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}C - C{H_2} - CHO} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}\xrightarrow{\Delta }$
Which of these reaction(s) will not produce Saytzeff product ?
$(a)$ The $pH$ of a mixture containing $400\, mL$ of $0.1\, M\, H_2SO_4$ and $400\, mL$ of $0.1\, M\, NaOH$ will be approximately $1.3$.
$(b)$ Ionic product of water is temperature dependent.
$(c)$ A monobasic acid with $K_a = 10^{-5}$ has a $pH = 5$. the degree of dissociation of this acid is $50\%$.
$(d)$ The Le Chatelier’s principle is not applicable to common-ion effect.
The correct statements are:
| List $I$ (Amines) | List $II$ $\left( pK _{ b }\right)$ |
| $A$ Aniline | $I$ $3.25$ |
| $B$ Ethanamine | $II$ $3.00$ |
| $C$ $N-$Ethylethanamine | $III$ $9.38$ |
| $D$ $N, N-$Diethylethanamine | $IV$ $3.29$ |
Choose the correct answer from the options given below :-