MCQ
$\int_{ - 1}^1 {{{\sin }^3}x{{\cos }^2}x\,dx = } $
- ✓$0$
- B$1$
- C$\frac{1}{2}$
- D$2$
Since the function is an odd function.
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Let f : N → R be the function defined by
$\text{f}(\text{x})=\frac{2\text{x}-1}{2}$ and g : Q → R be another function defined by g(x) = x + 2. Then $(\text{gof})\frac{3}{2}$ is: