MCQ
$\int_{\, - \,2}^{\,2} {\,\left| {\,[x]\,} \right|\,dx = } $
- A$1$
- B$2$
- C$3$
- ✓$4$
$ = \int_{ - 2}^{ - 1} {2dx\,\,} + \int_{ - 1}^0 {1dx + \int_0^1 {0\,dx + } } \int_1^2 {1dx} $
$ = 2[x]_{ - 2}^{ - 1} + [x]_{ - 1}^0 + 0 + [x]_1^2$
$ = 2( - 1 + 2) + (0 + 1) + (2 - 1) = 2 + 1 + 1 = 4.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| X: | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| P(X): | 0.15 | 0.23 | 0.12 | 0.10 | 0.20 | 0.08 | 0.07 | 0.05 |
Find the events E = {X : X is a prime number}, F{X : X < 4}, the probability $\text{P}(\text{E}\cup\text{F})$ is:
$S_1$ : If $f(x)$ is a differentiable function with $f'(x)$ = $0$ in $(a, b)$ and $f(x)$ is increasing in $(a, b)$ , then $\frac {f(x)}{f\ '(x)}$ is also increasing in $(a, b).$
$ S_2$ : Both $sin\ x$ and $tan\ x$ are increasing function in $(0,\frac{\pi}{2})$. Which of the following is true