_ - 2 ^2 |1 - x^2 | ,dx = - Vidyadip

MCQ

$\int_{ - 2}^2 {|1 - {x^2}|\,dx = } $

A
$2$
✓
$4$
C
$6$
D
$8$

✓

Answer

Correct option: B.

$4$

b
(b) $\int_{-2}^{-1}{|1-{{x}^{2}}|\,dx+\int_{-1}^{1}{|1-{{x}^{2}}|\,dx-\int_{1}^{2}{|1-{{x}^{2}}|\,dx}}}$

$ + \int_1^2 {|1 - {x^2}|dx} $

$= - \int_{ - 2}^{ - 1} {(1 - {x^2})\,dx + \int_{ - 1}^1 {(1 - {x^2})\,dx - \int_1^2 {(1 - {x^2})\,dx} } } $

$= \frac{4}{3} + \frac{4}{3} + \frac{4}{3} = 4.$

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