_ ^ a^x ;da = - Vidyadip

MCQ

$\int_{}^{} {{a^x}\;da = } $

A
$\frac{{{a^x}}}{{{{\log }_e}a}} + c$
B
${a^x}{\log _e}a + c$
✓
$\frac{{{a^{x + 1}}}}{{x + 1}} + c$
D
$x{a^{x - 1}} + c$

✓

Answer

Correct option: C.

$\frac{{{a^{x + 1}}}}{{x + 1}} + c$

c
(c)$\int_{}^{} {{a^x}da} = \frac{{{a^{x + 1}}}}{{x + 1}} + c.$

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