MCQ
$\int_{ - \frac{1}{2}}^{\,\frac{1}{2}} {\cos x\,\ln \frac{{1 + x}}{{1 - x}}dx} $ is equal to
  • $0$
  • B
    $1$
  • C
    $2$
  • D
    $ln \, 3$

Answer

Correct option: A.
$0$
a
(a) $I = \int_{ - 1/2}^{1/2} {\cos x\ln \left( {\frac{{1 + x}}{{1 - x}}} \right)\,dx} $

$\cos x\ln \left( {\frac{{1 + x}}{{1 - x}}} \right)$ is an odd function, $ \because f( - x) = - f(x)$)

$\therefore$  $I = 0$.

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