Question
$\int\frac{-1}{\text{y}^2}\text{dy}$ is:
- $\frac{1}{\text{y}}$
- 1 - y
- y
- 1 + y
Solution:
$\int\frac{-1}{{\text{y}}^2}\text{dy}$
$=-\int\text{y}^{-2}\text{dy}$
$=\text{y}^{-1}=\frac{1}{\text{y}}$
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