MCQ
$\int_{}^{} {\frac{{{{({{\tan }^{ - 1}}x)}^3}}}{{1 + {x^2}}}\,dx = } $
- A${({\tan ^{ - 1}}x)^4} + c$
- ✓$\frac{{{{({{\tan }^{ - 1}}x)}^4}}}{4} + c$
- C$2{\tan ^{ - 1}}x + c$
- D$2{({\tan ^{ - 1}}x)^2} + c$
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$x+y+\sqrt{3} z=0$
$-x+(\tan \theta) y+\sqrt{7} z=0$
$x+y+(\tan \theta) z=0$
has non-trivial solution. Then $\frac{120}{\pi} \sum_{\theta \in s} \theta$ is equal to