MCQ
$\int \frac{(x-3) e^x}{(x-1)^3} d x=$ _________ + C.
- A$\frac{e^x}{(x-1)^3}$
- B$\frac{e^x}{(x-3)^3}$
- C$\frac{e^x}{(x-3)^2}$
- D$\frac{e^x}{(x-1)^2}$
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