MCQ
$\int \frac{(x-3) e^x}{(x-1)^3} d x=$ _________ + C.
  • A
    $\frac{e^x}{(x-1)^3}$
  • B
    $\frac{e^x}{(x-3)^3}$
  • C
    $\frac{e^x}{(x-3)^2}$
  • D
    $\frac{e^x}{(x-1)^2}$

Answer

SELF

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