MCQ
$\int {\left( {{{\sin }^4}x - {{\cos }^4}x} \right)\,dx = } $
  • A
    $ - \frac{{\cos 2x}}{2} + c$
  • $ - \frac{{\sin 2x}}{2} + c$
  • C
    $\frac{{\sin 2x}}{2} + c$
  • D
    $\frac{{\cos 2x}}{2} + c$

Answer

Correct option: B.
$ - \frac{{\sin 2x}}{2} + c$
b
(b)$\int {({{\sin }^4}x - {{\cos }^4}x)dx} = \int {({{\sin }^2}x - {{\cos }^2}x)} \,({\sin ^2}x + {\cos ^2}x)\,dx$
$ = \int {({{\sin }^2}x - {{\cos }^2}x)\,dx} $$ = - \int_{}^{} {({{\cos }^2}x - {{\sin }^2}x)dx} $
$ = - \int_{}^{} {\cos 2x\,dx} $$ = \frac{{ - \sin 2x}}{2} + c$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the projections of the line segment AB on the coordinate axes are 12, 3, k and AB = 13 then k2 - 2k + 3  is equal to:
If for some $\alpha$ and $\beta$ in $R,$ the intersection of the following three planes  $x+4 y-2 z=1$ ; $x+7 y-5 z=\beta$ ; $x+5 y+\alpha z=5$ is a line in $\mathrm{R}^{3},$ then $\alpha+\beta$ is equal to
Let $|M|$ denote the determinant of a square matrix $M$. Let $g:\left[0, \frac{\pi}{2}\right] \rightarrow R$ be the function defined by

$g(\theta)=\sqrt{f(\theta)-1}+\sqrt{f\left(\frac{\pi}{2}-\theta\right)-1}$

where

$f(\theta)=\frac{1}{2}\left|\begin{array}{ccc}1 & \sin \theta & 1 \\ -\sin \theta & 1 & \sin \theta \\ -1 & -\sin \theta & 1\end{array}\right|+\left|\begin{array}{ccc}\sin \pi & \cos \left(\theta+\frac{\pi}{4}\right) & \tan \left(\theta-\frac{\pi}{4}\right) \\ \sin \left(\theta-\frac{\pi}{4}\right) & -\cos \frac{\pi}{2} & \log _e\left(\frac{4}{\pi}\right) \\ \cot \left(\theta+\frac{\pi}{4}\right) & \log _e\left(\frac{\pi}{4}\right) & \tan \pi\end{array}\right|$.

Let $p (x)$ be a quadratic polynomial whose roots are the maximum and minimum values of the function $g(\theta)$, and $p(2)=2-\sqrt{2}$. Then, which of the following is/are TRUE ?

$(A)$ $p \left(\frac{3+\sqrt{2}}{4}\right)<0$

$(B)$ $p \left(\frac{1+3 \sqrt{2}}{4}\right)>0$

$(C)$ $p \left(\frac{5 \sqrt{2}-1}{4}\right)>0$

$(D)$ $p \left(\frac{5-\sqrt{2}}{4}\right)<0$

Let $\overrightarrow{A}=i+j+k$ , $\overrightarrow B = i,\,\overrightarrow C = {C_1}i + {C_2}j + {C_3}k$. If ${C_2} = - 1$, and ${C_3} = 1$, then to make three vectors coplanar
If $\int {{x^5}{e^{ - 4{x^3}}}\,dx = \frac{1}{{48}}{e^{ - 4{x^3}}}f\left( x \right) + C} $, where $C$ is a constant  of integration, then $f(x)$ is equal to
Let $\vec b$ and $\vec c$ be non-collinear vector satisfying $\vec a \times \left( {\vec b \times \vec c} \right) + \left( {\vec a.\vec b} \right)\vec b = \left( {4 - 2x - \sin y} \right)\vec b + \left( {{x^2} - 1} \right)\vec c$ and $\left( {\vec c.\vec c} \right)\vec a = \vec c$ , then $x$ is equal to
The system of equations $\begin{array}{l}\alpha x + y + z = \alpha - 1\\x + \alpha y + z = \alpha - 1\\x + y + \alpha z = \alpha - 1\end{array}$ has no solution, if $\alpha $ is
Which of the following statements is correct?
  1. Every LPP admits an optimal solution
  2. A LPP admits unique optimal solution
  3. If a LPP admits two optimal solution it has an infinite number of optimal solutions
  4. The set of all feasible solutions of a LPP is not a converse set
The area (in $sq. units$) of the region $A = \left\{ {\left( {x,y} \right):\frac{{{y^2}}}{2} \le x \le y + 4} \right\}$ is
If f: R → R be given by $f(\text{x})=(3-\text{x}^3)^{\frac{1}{3}},$ then fof(x) is:
  1. $\text{x}^{\frac{1}{3}}$
  2. x3
  3. x
  4. (3 - x3).