MCQ
$\int_{}^{} {\log x(\log x + 2)\;dx = } $
  • $x{(\log x)^2} + c$
  • B
    $x{(1 + \log x)^2} + c$
  • C
    $x[1 + {(\log x)^2}] + c$
  • D
    None of these

Answer

Correct option: A.
$x{(\log x)^2} + c$
a
(a) $I = \int_{}^{} {\log x(\log x + 2)\,dx} $
Put $\log x = t \Rightarrow {e^t} = x \Rightarrow {e^t}dt = dx,$ then
$I = \int_{}^{} {t(t + 2){e^t}dt} = {t^2}.\,{e^t} + c = x{(\log x)^2} + c.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the solution of the differential equation $(2 x+3 y-2) d x+(4 x+6 y-7) d y=0, y(0)=3$, is $\alpha x+\beta y+3 \log _e|2 x+3 y-\gamma|=6$, then $\alpha+2 \beta+3 \gamma$ is equal to
$\int\limits^{\frac{\pi}{3}}_{\frac{\pi}{6}}\frac{1}{1+\sqrt{\cot\text{x}}}\text{ dx}$ is :
The shortest distance between the lines $\frac{\text{x}-3}{3}=\frac{\text{y}-8}{-1}=\frac{\text{z}-3}{1}$ and, $\frac{\text{x}+3}{-3}=\frac{\text{y}+7}{2}=\frac{\text{z}-6}{4}$ is:
For a sufficiently large value of $n$ the sum of the square roots of the first $n$ positive integers i.e.$\sqrt 1  + \sqrt 2  + \sqrt 3  + ...................... + \sqrt n$ is approximately equal to
A person writes 4 letters and addresses 4 envelopes. If the letters are placed in the envelopes at random, then the probability that all letters are not placed in the right envelopes, is
Let $[t]$ denote the greatest integer less than or equal to $t$. Then the value of the integral $\int_{-3}^{101}\left([\sin (\pi x)]+e^{[\cos (2 \pi x)]}\right) d x$ is equal to
If $A$ is a square matrix, then $' A – A\ ’$ is a:
Construct a $3 \times 4$ matrix, whose elements are given by $a_{i j}=\frac{1}{2}|-3 i+j|$.
If $A$ is a $3 \times 3$ matrix and $| A |=2$, then $\left|3 \operatorname{adj}\left(|3 A| A^2\right)\right|$ is equal to $.........$.
Let $f$ be a twice differentiable function on $R$. If $f^{\prime}(0)=4$ and $f(x)+\int_{0}^{x}(x-t) f^{\prime}(t) d t=\left(e^{2 x}+e^{-2 x}\right) \cos 2 x+\frac{2}{a} x$ then $(2 a+1)^{5} a^{2}$ is equal to $\dots\dots$