_ ^ cose c ^2 x ;dx is equal to - Vidyadip

MCQ

$\int_{}^{} {{\rm{cose}}{{\rm{c}}^2}x\;dx} $ is equal to

A
$\cot x + c$
✓
$ - \cot x + c$
C
${\tan ^2}x + c$
D
$ - {\cot ^2}x + c$

✓

Answer

Correct option: B.

$ - \cot x + c$

b
(b)$\int_{}^{} {{\rm{cose}}{{\rm{c}}^{\rm{2}}}x\,dx} = - \cot x + c$.

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