MCQ
$\int_{}^{} {\sec x\;dx = } $
  • A
    $\log \tan \left( {\frac{\pi }{8} + \frac{x}{2}} \right) + c$
  • $ - \log (\sec x - \tan x) + c$
  • C
    $\log (\sec x - \tan x) + c$
  • D
    None of these

Answer

Correct option: B.
$ - \log (\sec x - \tan x) + c$
b
(b)$\int_{}^{} {\sec x\,dx} = \log (\sec x + \tan x) + c$
$ = \log \left( {\frac{1}{{\sec x - \tan x}}} \right) + c$

$= - \log (\sec x - \tan x) + c$.

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