MCQ
$\int_{}^{} {\tan (3x - 5)\sec (3x - 5)\;dx = } $
- A$\sec (3x - 5) + c$
- ✓$\frac{1}{3}\sec (3x - 5) + c$
- C$\tan (3x - 5) + c$
- DNone of these
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${I_1} = \int_0^1 {{e^{ - x}}{{\cos }^2}x\,dx} , \,\, {I_2} = \int_0^1 {{e^{ - {x^2}}}} {\cos ^2}x\,dx$
${I_3} = \int_0^1 {{e^{ - {x^2}}}dx} ,\,\,{I_4} = \int_0^1 {{e^{ - {x^2}/2}}dx} ,$ then