MCQ
$\int x^2 e^{x^3} d x$ equals
- ✓$\frac{1}{3} e^{x^3}+C$
- B$\frac{1}{3} e^{x^4}+C$
- C$\frac{1}{2} e^{x^3}+C$
- D$\frac{1}{2} e^{x^2}+C$
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, where $\mathrm{C}$ is the constant of integration. Then $\alpha+\frac{\gamma}{\beta}$ is equal to :
| $X:$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ | $7$ | $8$ |
| $P(X):$ | $0.15$ | $0.23$ | $0.12$ | $0.10$ | $0.20$ | $0.08$ | $0.07$ | $0.05$ |