_0^1 (1 - x) ^9 dx = - Vidyadip

MCQ

$\int_0^1 {{{(1 - x)}^9}dx = } $

A
$1$
✓
$\frac{1}{{10}}$
C
$\frac{{11}}{{10}}$
D
$2$

✓

Answer

Correct option: B.

$\frac{1}{{10}}$

b
(b) Required value =$\left[ {\frac{{ - {{(1 - x)}^{10}}}}{{10}}} \right]_0^1 = \frac{1}{{10}}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 7.2 definite integral→7.2 definite integral — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Find the principal value of $\cot ^{-1}(\sqrt{3})$

In a parallelogram $ABCD$, $\left| {\overline {AB} } \right| = a\,,\,\left| {\overline {AD} } \right| = b$ and $\left| {\overline {AC} } \right| = c$ then $\overline {DA} $. $\overline {AB} $ has the value

If ${\tan ^{ - 1}}x - {\tan ^{ - 1}}y = {\tan ^{ - 1}}A,$ then $A$

If A = {1, 2, 3}; B = {3, 4, 5}; C = {4, 6}, then $\text{A}\times(\text{B}\cap\text{C})=?$

$\mathop {\lim }\limits_{n \to \infty } {\left( {\frac{{\left( {n + 1} \right)\left( {n + 2} \right) \ldots .\;3n}}{{{n^{2n}}}}} \right)^{\frac{1}{n}}} = $

$\int\log_{10}\text{xdx}=$

$\log_{\text{e}}10.\text{x}\log_{\text{e}}\big(\frac{\text{x}}{\text{e}}\big)+\text{c}$
$\log_{10}\text{e.x}\log_{\text{e}}\big(\frac{\text{x}}{\text{e}}\big)+\text{c}$
$\log_{10}\text{e.x}\log_{\text{e}}\big(\frac{\text{x}}{\text{e}}\big)+\text{n}$
$\log_{10}\text{e.x}\log_{\text{e}}\big(\frac{\text{x}}{\text{n}}\big)+\text{n}$

If $y=y(x)$ is the solution of the differential equation $\frac{d y}{d x}+\frac{4 x}{\left(x^2-1\right)} y=\frac{x+2}{\left(x^2-1\right)^{\frac{5}{2}}},x > 1$ such that $y(2)=\frac{2}{9} \log _e(2+\sqrt{3})$ and $y(\sqrt{2})=$ $\alpha \log _e(\sqrt{\alpha}+\beta)+\beta-\sqrt{\gamma}, \alpha, \beta, \gamma \in N$, then $\alpha \beta \gamma$ is equal to $........$.

If $\frac{{d[f(x)]}}{{dx}} = g(x)$ for $a \le x \le b,$ then $\int_a^b {f(x)\,\,g(x)\,dx} $ equals

Area of region enclosed by locus of $z$ given by $Arg (z + i) -Arg(z -i) = \frac{2 \pi}{3}$ and imaginary axis is-

If $A$ is a square matrix, then $A-A^{\prime}$ is a