MCQ
$\int_0^{1.5} {[{x^2}]\,dx} $, where $[\,\,.\,\,]$ denotes the greatest integer function, equals
- A$2 + \sqrt 2 $
- ✓$2 - \sqrt 2 $
- C$ - 2 + \sqrt 2 $
- D$ - 2 - \sqrt 2 $
$ = 0 + \int_1^{\sqrt 2 } {1dx + \int_{\sqrt 2 }^{1.5} {2dx = \sqrt 2 - 1 + 3 - 2\sqrt 2 = 2 - \sqrt 2 } } $.
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If $I_1 = \int\limits_{\frac{\pi }{6}}^{\frac{\pi }{3}} \, f (\tan\, \theta + \cot\, \theta )\cdot sec^2\, \theta\, d\, \theta$ &
$I_2 = \int\limits_{\frac{\pi }{6}}^{\frac{\pi }{3}} \, f (\tan\, \theta + \cot\, \theta )\cdot cosec^2\, \theta\, d \, \theta$ ,
then the ratio $\frac{{{I_1}}}{{{I_2}}}$ :